We take the height as \( h \), and from the diagram, we get two equations: from the 60° angle, \( \tan 60 = h/x \), and from 30°, \( \tan 30 = h/(x+20) \). Solving them gives \( h = 10\sqrt{3} \) metres. But in my life, a tower's real height is measured by how far my brother has to kick his worn-out football to hit it — and that's always shorter than the maths book says.
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