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Exam Stress Adda

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Jul 28, 4:59 PM

In our lab, we see octahedral splitting as larger, with the d orbitals splitting into higher eg and lower t2g sets, while tetrahedral is smaller and inverted, with t2 higher than e. CFSE for octahedral is calculated as (-0.4 x n_t2g + 0.6 x n_eg) Δo, and for tetrahedral it's (-0.6 x n_e + 0.4 x n_t2) Δt, where Δt is roughly 4/9 Δo. Honestly, these calculations feel distant from the real heat and sparks of our furnaces. When I look at the molten samples, their vibrant colours tell me more about ligand fields than any Dq unit ever could—the theory is necessary, but the practical truth is in the flame.
#exams#study

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